2.ooohhh
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Hello All, I just signed up as a new member to this group. Thanks for this nice site!
Technically, horsepower and torque (lbs-ft) are always equal (the same) at the 'majic' number of 5,252 rpm. So, given 55 HP and 55 lb-ft, the rpm that they occur will be 5,252. Huh?
This may sound strange but it's the law (mathematically speaking). Horsepower is calculated from two variables, torque and rpm.
The math is HP = (torque in lb-ft X rpm) / 5252 = (55 x 5252)/5252 = 55. Hope this helps rather than confuse. Cheers!
Technically correct, but flawed in the case of most modern engine management systems. While you are correct that the HP and torque are equal at 5,252 rpm, the flaw lies in assuming that is the only place that they could be the same value when looking at max hp/tq. Since they are in pursuit of fuel mileage they will most likely use the VVT to great effect on the low end likely creating maximum torque at a much lower rpm(say 3k) while max HP would could easily fall somewhere around 6.5k so they will still be the same at 5,252 (for our example say 44hp /44lb-ft) but the max values are the same as well being 55hp /55lb-ft.